(2x^2-3x)/5-3

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Solution for (2x^2-3x)/5-3 equation:


x in (-oo:+oo)

(2*x^2-(3*x))/5-3 = 0

(2*x^2-3*x)/5-3 = 0

(2*x^2-3*x)/5+(-3*5)/5 = 0

2*x^2-3*x-3*5 = 0

2*x^2-3*x-15 = 0

2*x^2-3*x-15 = 0

2*x^2-3*x-15 = 0

DELTA = (-3)^2-(-15*2*4)

DELTA = 129

DELTA > 0

x = (129^(1/2)+3)/(2*2) or x = (3-129^(1/2))/(2*2)

x = (129^(1/2)+3)/4 or x = (3-129^(1/2))/4

(x-((3-129^(1/2))/4))*(x-((129^(1/2)+3)/4)) = 0

((x-((3-129^(1/2))/4))*(x-((129^(1/2)+3)/4)))/5 = 0

((x-((3-129^(1/2))/4))*(x-((129^(1/2)+3)/4)))/5 = 0 // * 5

(x-((3-129^(1/2))/4))*(x-((129^(1/2)+3)/4)) = 0

( x-((129^(1/2)+3)/4) )

x-((129^(1/2)+3)/4) = 0 // + (129^(1/2)+3)/4

x = (129^(1/2)+3)/4

( x-((3-129^(1/2))/4) )

x-((3-129^(1/2))/4) = 0 // + (3-129^(1/2))/4

x = (3-129^(1/2))/4

x in { (129^(1/2)+3)/4, (3-129^(1/2))/4 }

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